David Roberson <[email protected]> wrote:
> I do not get anywhere near to the 3 to 1 excess power out over input power > that is reported. I am seeing a 1.25 ratio instead of 3.0 or so. > Oh, I think you did see the 3 to 1 excess, and the 6:1 as well. Keep looking! Look at Table 1. You got 1:1.25 for the water on Oct. 21. Right? I estimate 1:1.35, which is close enough. Now look at Oct. 20, which got a much better ratio with the water, 1:2.29. NOW add in the heat captured by the stainless steel reactor vessel. The thermal mass of the reactor is larger than that of the water, so I estimated that the vessel captures 60% of the heat, and the water 40%. So, the combined ratio for Oct. 20, for the water and stainless steel, is 1:5.69 Try applying your method to the Oct. 20 data and see if you get an answer in the same ballpark. Additional calibrations are underway. I believe I will soon be able to confirm that the reactor vessel is, in fact, capturing 60% of the heat. - Jed
