His claim is 1 tonne of thrust per kilowatt. One tonne of thrust will accelerate an object. An object under the acceleration of gravity will be countered by the thrust, costing 48 kilowatts of power in the process. This is not the same as suspending an object by a rope or something. Are you suggesting that there is no theoretical limit as to how much power, applied as thrust, is needed to suspend an object weighing a tonne? Or are you suggesting that my math is wrong and that there is a lower number? If the number is lower, then how do you arrive at it?
Craig On Sun, May 10, 2015 at 10:48 PM, <mix...@bigpond.com> wrote: > In reply to Craig Haynie's message of Sun, 10 May 2015 18:07:28 -0400: > Hi, > [snip] > > It doesn't cost any energy at all to support a car. The ground does this > just > fine with no energy expenditure. E = F . d. If d = 0, then E = 0. > I'm not sure how this applies to an EM drive (if at all), but perhaps it > needs > to be taken into consideration? > > >Hello! > > > >I was hoping the Vorts could help me with this. Roger Shawyer, at minute > >2:56 in this video, claims that the next generation EM Drive could > >generation 1 tonne of thrust per kilowatt of power. This means that a 1 > >tonne car should be able to hover above the ground for the price of one > >kilowatt. However, my calculation shows that to be about 48 times a > >theoretical maximum. > > > >Here is the video where he makes the claim at 2:56. > > > >http://tinyurl.com/ko5v6h7 > > > >But here is my calculation for a theoretical maximum, calculated two > >different ways: > > > > - > > > > A joule is a watt-second > > - > > > > A watt is a joule / second > > - > > > > The power required to hover an object is the same power required to > > increase the speed of the object from rest, in a weightless > environment, to > > 9.8 m/s in one second. We know this because the pull of gravity is 9.8 > > meters/second2. > > - > > > > The kinetic energy in an object travelling at 9.8 m/s = 1/2 * m * v2. > So > > for a car of 1000 kg, the energy = 1000 / 2 * 9.82 = 48,020 joules = 48 > > kilowatts to do this in one second. > > - > > > > This power should be 1/2 the power to raise an object of the same mass, > > to a height of 9.8 meters in one second, since it would require twice > as > > much energy to do this. > > - > > > > The formula to determining how much energy it takes to raise something > > to height = E = m * g (gravitational constant) * h = 1000 * 9.8 * 9.8 = > > 96,040 watts-seconds = 96 kilowatts to do this in one second. So it > agrees > > with the previous result. > > > >So, I don't understand how any device could hover an object with the mass > >of a tonne for less than a theoretical 48 kilowatts. Any thoughts on this > >would be appreciated. > > > >Craig Haynie ( Manchester, NH) > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
