Vortex down? Sending this again:
On Jan 5, 2006, at 11:43 AM, Stephen A. Lawrence wrote:
I don't know if I go along with the fusion speculation, though.
Well, the formation low energy D or 3He by electron catalysis in
light water is to me far more palatable than a proton reaction with
potassium or other highly charged nucleus. If experimental evidence
proves heavy element reaction with hydrogen then we have to accept
that (not that I think it is yet conclusive and thus must be
accepted.) However, if we can accept that possibility, then it seems
almost trivial to accept the formation of D and He3 in light water,
or in heavy water T or a neutral 4He* (which is essentially a de-
energized quadraneutron) that can form helium or create mass 4
changes without strong signatures.
The degree of de-energization at the moment of fusion depends on just
how small the de-energized fused particle is upon initial waveform
collapse. Given that it can be string sized, essentially all the
energy of the reactants is then returned to the vacuum, followed by a
permanent energy borrowing to "expand" the strings quantum waveforms
to normal size. We thus not only have ZPE fueled atomic expansion,
we have ZPE fueled nuclear expansion, followed by atomic expansion of
the leptons.
The most plausible possible mechanism you mentioned for the blue
glow seemed to me to be the last one, in which the insulating
layer, in combination with the solution itself, is said to form a
semiconductor LED.
True, but the possibility of *both* types of glow is not excluded
either.
If I understood it, you're suggesting that the insulator+solution
might form the equivalent of _two_ reversed diodes in parallel
(_not_ series), and the one with the higher resistance and higher
forward voltage drop is the one associated with the blue glow.
I suggest that the insulator + solution forms a single diode when the
insulator is properly "conditioned". Given two properly conditioned
electrodes in an AC cell, they act like back-to-back diodes, and thus
act like a capacitor - though one with a bit of a bypass resistor.
Given one conditioned electrode and one electrode with no conditioned
insulator, the cell acts like a diode. In that case the conditioned
electrode is a cathode when conducting, an anode when it opposes
current flow. This effect I attributed to low anion mobility in the
interphase. Proton mobility is comparatively high everywhere in the
cell.
So, the glow shows when the high-drop diode is _forward_ biased, as
we would expect from solid state LED experience. (A first glance
at this situation, before reading your paper, made it seem like the
glow was associated with a _reverse_ biased diode, which seemed
harder to understand.)
Er ... at least, I think that's what you said?
No, just the opposite. A conditioned electrode produces the glow
when it is reverse biased, i.e. when it is an *anode* in the cell.
It is accepting electrons from the electrolyte. It is creating free
protons in an extraordinarily strong electrostatic field at its
surface. The experimental evidence for this was all carefully
described in <http://www.mtaonline.net/~hheffner/BlueAEH.pdf> and in
the related posts here on vortex around Feb. 2002.
I hope that is helpful - it is not easy to describe these concepts.
Horace Heffner
