Exactly!
Te energy must go somewhere, and conventionally is
converted into heat instead of mass.

--- "Stephen A. Lawrence" <[EMAIL PROTECTED]> wrote:

> 
> 
> Merlyn wrote:
> > Having loads of fun here
> > 
> > <my email truncated the interesting and relevant
> parts
> > of the previuos messages, so no quote possible>
> > 
> > Horace, your gedanken experiment involving the
> dropped
> > rock neglects the fact that light carries
> momentum. 
> > In order for the rock to be turned into light
> > ttraveling the opposite direction, a force must be
> > applied to reverse its momentum. Equally, Einstein
> at
> > the top of the ladder must apply a force when he
> > catches the light to stop it and turn it into a
> > stationary rock.
> 
> Actually it was my gedanken, or rather my quote of
> Einstein's gedanken 
> experiment.  But you're right, force is necessary to
> change the momentum 
> of the rock/photon.
> 
> But we can deal with the momentum issue.  The rock
> can exchange momentum 
> with the person who catches it _without_ exchanging
> more than a 
> negligible amount of energy, and it's the total
> energy we were concerned 
> with.  Just make the planet on which the person who
> catches it is 
> sitting sufficiently massive, so that the planet's
> motion, and by 
> extension the motion of the person, is negligible.
> 
> We see this effect all the time in real life. 
> Bounce a ball off a hard, 
> solid wall.  The ball's momentum reverses, which
> implies the wall gained 
> momentum equal to twice what the ball had to start
> with, but if it's a 
> good hard rubber ball and the wall is good and
> solid, the ball loses 
> almost none of its energy.  The wall gains momentum
> but (almost) no energy.
> 
> A massive mirror, for another example, will flip the
> momentum vector of 
> a beam of light very nicely while absorbing
> essentially none of the energy.
> 
> The reason is that "net impulse" -- transfer of
> momentum -- depends only 
> on the duration of the applied force, while "work"
> -- energy transfer -- 
> depends on the force and the distance the body it
> acts on moves during 
> the application of the force.  If the body is
> massive and hence doesn't 
> move more than a miniscule amount during application
> of the force, only 
> a negligible amount of energy will be transfered.
> 
> Finally, if you throw a _sticky_ ball at a wall, and
> it sticks but 
> doesn't bounce off, _and_ if the wall is good and
> solid (and massive), 
> you find that the wall gains momentum equal to what
> the ball had, _but_ 
> it still gains almost no kinetic energy.  Instead,
> the ball's kinetic 
> energy (almost) all turns into heat.
> 
> 


Merlyn
Magickal Engineer and Technical Metaphysicist

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