I have always thought that the gas insulator must be isotopically pure. Deuterium is a lot easier to get off COTS compared to isotopically pure prodium. This reflects the need to form a Bose condensate on the surface of the mesh. This requirement for the formation of a condensate also reflects why impurities such as water and nitrogen are a reaction show stopper. My guess is that pure protium will work just as well as deuterium in the Mizuno mesh reactor.
On Thu, Jun 27, 2019 at 4:18 PM JonesBeene <[email protected]> wrote: > > > > > *From: *Jed Rothwell <[email protected]> > > > > - Two or three people have suggested to me that Mizuno's reaction must > be unstable because it is exponential and self-heating. I do not think so. > > But Mizuno and other have suffered runaway reactions in the past which are > completely unexplained to this day since they did not leave behind > significant activation of materials.. > > The best rationale for the belief that this design will not runaway is the > very low inventory of reactant and/or the fact that the gainful reaction is > not nuclear fusion. > > Not sure if the inventor or anyone else has calculated the inventory when > it is operating but it could be as low as a milligram, no? > > 300 Pa is about .003 atm. D2 gas weighs in at 4 g/mol. By Avogadro's law > 1 mole of every gas occupies 22.4 L. For convenience we can guesstimate the > volume of the reactor is 2.24 L so that it holds one tenth of a mole. > Therefore, the mass of D2 could be as low as .0012 grams during operation. > > OTOH - a milligram of deuterium would definitely create a runaway if it > all fused in a short time… > > ERGO – one big reason for thinking a runaway will not happen is that > nuclear fusion is not the gainful reaction.. > > > > > > > > >
