In reply to [email protected]'s message of Thu, 5 May 2022 05:47:34 +0000: Hi Bob,
I think the standard answer is because of the ZPE. The particles in the nucleus are constantly in motion, and occasionally that motion gives rise to a rearrangement of the particles that allows a radionuclide to decay. IIRC, there is a fairly strong correlation between decay energy and half life (for a given type of decay). Generally, the larger the decay energy, the shorter the half life. However the point I was trying to make, was that if your method worked, then why doesn't it get used by radionuclides, which instead appear to decay by particle emission &/or gamma radiation? >Robin-- > >Why does nuclear decay happen routinely? > >The swap of potential energy of a QM system is not without restrictions os >regarding conservation of angular momentum and conservation of total energy. >In addition the allowable quantum states that are phonic states with specific >non continuous values of kinetic emerge AND angular momentum. The angular >momentum must b a multiple of h/2 pie. > >The proper matching of parameters within a arbitrary QN system does not occur >very often in nature. However it can be engineered in LENR reactors. > >Key parameters include startimg material QM enerfy states and and angular >momentum quantum states and phonic energy states. Magneticc fields >including resonances are also important to modify QM system allowed energy >states . > > >Bob Cook > >From: Robin<mailto:[email protected]> >Sent: Wednesday, May 4, 2022 3:03 PM >To: [email protected]<mailto:[email protected]> >Subject: Re: [Vo]:Laser Cooling -> Cooling with radiation > >In reply to [email protected]'s message of Wed, 4 May 2022 16:49:08 >+0000: >Hi Bob, >[snip] >>Radiation cooling is how the final process of LENR works. >> >>The first step is to swap nuclear potential energy to kinetic spin phonic >>energy of a QM atom (including electronic structure) which is classical >>thermal energy subject to common radiation cooling in the second step. > >...then one wonders why this doesn't apply to the normal decay of >radioisotopes? >If no one clicked on ads companies would stop paying for them. :) If no one clicked on ads companies would stop paying for them. :)
