Frank.
We Know that particle Energy E = mc^2 = 8.19e-14 joule for an electron or positron(9.1E-31 kg) ,
and E = h*f or f = E/h = 8.19e-14/6.626e-34 = 1.236e20 Hz.
E = hc/lambda and f = c/lambda = 1.23e20 Hz....
Or:
Lambda = hc/E or h/mc .
Where is the problem for an EM energy pulse reflecting back and forth on a doubly open-ended
lossless transmission line at 1.23e20 times per second?
Fred
----- Original Message -----Sent: 3/18/2006 8:19:39 AMSubject: Re: Circular Particles as Parallel Resonant "Tank Circuits"Resonant frequency f = 1/(LC)^1/2 = 1.23e20 Hz.Back to trig school. :-)Fred<snip>Thank you Fred. In your formula what is L? It is not known. You have two unknowns L and C. You formula is unsolvable. A better way to represent resonant frequency is.Resonant frequency f = K/(M)^1/2 = 1.23e20 HzWe now know the mass M of elementary particle. The only unknown is K. We can solve for it. What does the elastic constant K physically represent? Knowing that K is conceptually equivalent to 1/C and that elementary particles have the highest frequency possible. C represents a mimimum of stray capacitance or a mechanical elastic limit. I have traveled down this road and got a lot of answers.I have tried to get a paper published on the subject but, for the time being, I have given up dealing with journal editors.Frank Znidarsic.

