Frank.
 
We Know that particle Energy E = mc^2 = 8.19e-14 joule for an electron or positron(9.1E-31 kg) ,
and E = h*f  or f = E/h = 8.19e-14/6.626e-34 = 1.236e20 Hz.
E = hc/lambda and f = c/lambda = 1.23e20 Hz....
Or:
Lambda = hc/E or h/mc . 
 
Where is the problem for an EM energy pulse reflecting back and forth on a doubly open-ended
lossless transmission line at 1.23e20 times per second? 
 
Fred
 
 
----- Original Message -----
From:
To: [email protected]
Sent: 3/18/2006 8:19:39 AM
Subject: Re: Circular Particles as Parallel Resonant "Tank Circuits"

Resonant frequency f = 1/(LC)^1/2 = 1.23e20 Hz
.
 
Back to trig school.  :-)
 
Fred
 
 
<snip>
 
Thank you Fred.  In your formula what is L?   It is not known.   You have two unknowns L and C.  You formula is unsolvable.  A better way to represent resonant frequency is.
 
Resonant frequency f = K/(M)^1/2 = 1.23e20 Hz
 
We now know the  mass M of elementary particle.  The only unknown is K.  We can solve for it.  What does the elastic constant K physically represent?  Knowing that K is conceptually equivalent to 1/C  and that elementary particles have the highest frequency possible.  C represents a mimimum of stray capacitance or a mechanical elastic limit.  I have traveled down this road and got a lot of answers.
 
 
I have tried to get a paper published on the subject but, for the time being, I have given up dealing with journal editors.
 
 
Frank Znidarsic
 
.
 

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