Posted earlier:
>
> The Displacement Current in any particle I = C *dV/dt where C = eo * wavelength (hc/E)
> sets up an enormous B field.
> Another approach is I = q*f where f = c/wavelength = 19.7 amperes for the electron
> and 12,056 amperes for each of the three "quarks" in the proton.
>
> R = wavelength/2(pi) 3.86e-13 meters & 6.3e-16 meters for the radius of
> the electron and each of the 3 discs (quarks) stacked side-by-side in the proton
> 2 up or plus cw and 1 minus ccw giving an enormous "solenoid-like B field.
>
> This GSU interactive calculator will give you the value of the B field s.
> and total spin mcr = h/2(pi) will give acceleration c^/r
>
The square root of the ratio of the electrostatic force Fes = kq^2/R^2 = 2.30e-28 nt at 1.0 meter
to the gravitational force Fg = 6.67e-11 m^2 = 5.52e-71 for two electron masses
at 1.0 meter., ie., = square root of 4.17e42 =2.04e21 is the relativistic gamma
of the accelerated B field of the electron which results in a time-dilated charge
"hypocharge" (**q) = q/gamma = 1.6e-19/2.04e21 = 7.834e-41 coulombs.
OTOH since it is apparent that charge q is a result of EM Field "oscillations",
each of the three quarks making up the proton are time-dilated by
the square root of Fes/Fg = (2.30e-28/2.04e-65)^1/2 = 3.35e18
thus a "hypocharge" (*q) = 1.6e-19/= 4.76e-38 coulombs.
Since there are 1/(5.5e-28 )= 1.82e27 quarks/kilogram ,each with hypocharge 4.76e-38
coulombs the Electrogravity Force = 9.0e9(*q1x *q2/R^2 = 6.67e-11 newtons force
between them at 1.0 meter separation Same as conventional Fg).
OTOH, If one can develop a hypocharge from a rotating (accelerated B Field)
that can couple to that of the earth....?
Fred
