Nonsense.
 
The higher the frequency-energy  the shorter the wavelength hc/E = wavelength.
 
Wavelength/[2(pi)]  = Radius. 3.86e-13 meters for the electron and ~ 0.6 Fermi for the "quarks"
which is in close agreement with the ~.1.0e-15  meter radius measured for nuclei.
 
The positron-electron pairs are made from a 1.02 MeV photon with wavelength hc/E
and most likely the  Triad  (+  -   + )  of so-called "quarks" in a proton  (about 312 MeV each in the bound state)
were made from two pair of ~ 540 Mev Mesons where the "left out"  negative Meson decaying into an
electron. Hence the hydrogen atom.
 
Fred
----- Original Message -----
From: David Jonsson
To: [email protected]
Sent: 3/26/2006 10:06:17 AM
Subject: [Norton AntiSpam] Re: Gravitomagnetic Field Quantified

On 3/24/06, Frederick Sparber < [EMAIL PROTECTED]> wrote:
I don't think we are very far apart on the issue, David.
 
The Displacement Current in any particle I = C *dV/dt  where  C = eo * wavelength (hc/E)
sets up an enormous B field.
Another approach  is I = q*f  where f = c/wavelength = 19.7 amperes for the electron
and 12,056 amperes for each of the three "quarks" in the proton. 
 
Elementary charge * the speed of light = 4.8032042 × 10^-11 mA is the highest current an electron can have. Isn't it?
 
The quarks with even smaller charge could not have higher current.
 
David

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