Re: Electrogravity From Accelerated B Fields

[Frederick Sparber]

Going way out on a limb.

 

An 8 inch diameter 24 gauge aluminum sphere inside a

12 inch diameter 24 gauge aluminum sphere (~ 1.2 kg wt.) laid on the

table with the outer sphere grounded so it's ~2.22e-9 farad capacitance

can be charged with energy > 20 joules:

 

V = [20*1.2/(0.5*2.2e-9)]^1/2 = 147,000 volts

 

Connecting the inner sphere to a Van de Graaff at 150,000 volts

(or more) through a suitable feed-though insulator will

make the thing want to float.

 

If it doesn't, it's back to the old drawing board.  :-)

 

Fred

 

 ----- Original Message -----

From: Frederick Sparber

To: vortex-l

Sent: 4/7/2006 6:36:39 AM

Subject: Re: Electrogravity From Accelerated B Fields

In order to achieve 1.0  kg of weightlessness at the earth's

surface, ~ 20 joules of electrogravity energy  (as D.C.) must be stored

between the plate of a vacuum capacitor..

Thus for a pair of one meter square plates separated by 1/2 meter

the voltage V  required = (20/8.85e-12)^1/2 = 1.5 Megavolts.

Obviously to get any floating levitation the two plates of the capacitor

must have a combined mass of less than a kilogram.

Sphere-within-a-Sphere capacitors will eliminate ion wind/corona

problems if the radius of the inner sphere (a) is one meter

(to allow occupancy) and the radius of sphere (b) is 1.5 meters

C = 4(pi)8.85e-12/0.5 - 2.22e-10 farad.

The vacuum volume  between the spheres is about 36 cubic meters.

The material for the spheres requires 41 square meters of strong-conductive

material. Based on 24 gauge aluminum (~ 1.4 kg/meter^2) the

combined weight of the spheres is about 60 kg.

At 20 joules/meter^3 required to achieve weightlessness it will require

at 1300 joules to float.

V = [1300/(2*2.22e-10)]^1/2 = 3.4 Megavolts

Connecting additional sphere-in-sphere units together using  crawl-able

tubes-in-tubes  (parallel capacitance at the working voltage) will add to float capability.

 

TGIF

 

Anonymous   :-)