In reply to Michel Jullian's message of Wed, 7 Jun 2006 00:44:44 +0200: Hi Michel, [snip] >0.5E-10 x 1/200 = 0.25E-12 = 250E-15, OK but may I suggest fm rather than "F" >(symbol for Farad)
...also the symbol for Fermi ( 1E-15 m). > >I recall reading that muon catalyzed fusion couldn't produce excess heat, is >this true, and why? Yes, it's true. The problem is that the production of negative muons relies on energetic protons (from an accelerator), which is so inefficient that the energy release from the resulting fusion reactions can't compensate. However if the resulting fast neutrons were used in a fission reactor, all actinides could be used with 100% burn up. This would extend the U stockpile 10-100 fold, and leave no Pu for weapons. It could also dispose of existing Pu. BTW, Hydrinos don't suffer the same problem as muons because they release energy while being produced, rather than consuming it. > >> According to Mills, the radius of the Hydrino goes as the inverse >> of the shrinkage level, i.e. the smallest would be BR/137 ~= 386 >> F. >> According to me it goes as the inverse square of the level, which >> would mean that to get to 256 F, it would have to shrink to level >> 15. > >Why such a discrepancy? What's the radius law for normal hydrogen levels? Linear according to Mills (AFAIK), quadratic according to me and the rest of the World. [snip] >This would be nice, all is needed is sufficiently shrunken hydrinos, but how >do you get those? [snip] With long term confinement of a Hydrogen Argon/Helium plasma. (Or you "mine" them from fresh rain water from a thunderstorm that has sprites/jets soon after impact of a CME with the atmosphere). Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition provides the motivation, Cooperation provides the means.
