Might the Joe Cell "Processing/Electrolysis" be setting up conditions where the "combustion" in an ICE effects the uptake of Electronium by H+ ions?
> [Original Message] > From: Frederick Sparber <[EMAIL PROTECTED]> > To: <[email protected]> > Date: 6/8/2006 8:14:27 AM > Subject: Re: Electronium (Bound Ps-) Orbits vs Fractional Electron Orbits > > Michel Jullian wrote: > > > > Hi Fred, a very good idea to do such maths after the hydrino radiuses law > discussion! > > > > ----- Original Message ----- > > From: "Frederick Sparber" <[EMAIL PROTECTED]> > > To: "vortex-l" <[email protected]> > > Sent: Thursday, June 08, 2006 2:04 PM > > Subject: Re: Electronium (Bound Ps-) Orbits vs Fractional Electron Orbits > > > > > > > The potential V of a `particle with charge - q at a distance r > > > from a particle with charge + q equals V = k*q/r independent > > > of the mass of either particle. k = 1/4(pi)eo > > > > > > Hence an electron of mass 2 * 9.1E-31 kg (Electronium) has the same > potential > > > at r = 5.29E-11 meters as a regular electron with mass 9.1E-31 kg. > > > > Indeed. > > > > > > > > The velocity v = [2 V*q/r * (1/m)]^1/2 = [2 V*q/r (1/2m)]^1/2 at that > > > point is also the same (c * alpha or c/137 at a distance > > > r = 5.29E-11 meters, the bohr radius). > > > > Where does this come from? > > > The velocity in the classical Bohr ground state orbit. For the purest > a "Group Velocity" invoking the "Fine Structure Constant "Alpha" = > 0.00729729 > where c is the speed of light "Phase Velocity" or mcr = hbar = [h/2(pi)] > > > > > > > > OTOH, in order to equate an orbital centripetal force (Fc) mv^2/r with > > > a balancing electrostatic force (Fes) kq^2/r^2: > > > > > > mv^2/r = kq^2/r^2 r = kq^2/mv^2 > > > > Yes, I suppose relativistic effects can be neglected at c/137, and QM > effects ignored for now. The rest is not obvious to me, maybe you will have > enlightened me when I'll be back? (must be off right now) > > > Relativistic "Gamma" = E (kinetic)/Eo (mc^2) + 1 = [1/1- (v^2/c^2)]^1/2 > doesn't > get very pronounced at 218 eV (3.488E-17 joules) where mc^2 for the regular > electron equal 8.19E-14 Joule: (3.488E-17/8.19E-14) + 1 = 1.000425 less > yet > for a mass 2 * electron (Electronium) mass. > > I'm trying to enlighten myself on where an Electronium (stable/bound Ps- > particle) ground state > orbit will be. Then show that when it is shaken loose from atoms/molecules > and > taken up by the H+ ion,with release of energy exceeding the 13.6 eV bohr > ground state, > it is what Mills is calling a 'Fractional Orbit Electron-Hydrino". > > Without writing a book and unsettling the orthodox scientific > establishment. :-) > > Fred > > > > > > Michel > > > > > > > > It seems that a particle with mass 2m * v^2 will orbit at 1/2 the > > > bohr orbit radius of an electron with a potential V * q/0.5r > > > = 54.4 volts at an orbital velocity of v = [2 V*q/0.5r * (1/2m)]^1/2 > > > equal 3.1E6 meters/sec (the square root of 2 (1.414) times c/137). > > > > > > But, in order to satisfy quantum integers of c/137 velocity > > > requirements n (c/137) velocity v = 4.378E6 meters/sec and > > > radius r' = kq^2/2mv^2 = 6.61E-12 meters > > > and potential V = kq/r' = 218 volts. > > > > > > Fred > >
