Posted earlier:
>
> Particle Radius, R = kq^2/E
>
> Electron energy E = mc^2 = 8.19E-14 Joule
> R = 3.72E-15 meters or 3.72 Fermi
> Disk or Hoop (string circles ?)
>
> Proton energy E = mc^2 = 1.49E-10 Joule
> R = 2.0E-18 meters or 0.002 Fermi
> Or with 3 stacked "quark circles" making a proton
> E = 1.49E-19/3 Joule
> E = 4.98E-11 Joule
> Stack Radius R = 6.0E-18 meters or 0.006 Fermi
>
>
>
> How close can a bare proton (H+) approach a hydrogenic (one electron) atom?
>
> Or, how far into an oxygen atom of an H2O molecule does a hydrogen atom
> need to go in order to capture one of the high energy inner shell electrons of the
> oxygen atom which can then be taken up to orbit the proton with the same energy
> it had in it's oxygen orbit, allowing that one of the outer (low energy) electrons
> of the H2O molecule will replace the proton-captured oxygen electron with
>a commensurate energy release?
>
Based on the small size of a proton, and the propensity for hydrogen to
diffuse into Palladium and other metals, why not visualize the protons
formed in water near the right type of stainless steel electrodes diffusing
into and through them concurrently picking up electrons in the high energy
shells and forming hydrinos that dump energy in the compression-combustion
cycle of the ICE?
Check out the 700 eV to 7 Kev electron levels for Iron, Nickel, Chromium,
Manganese, and others in the X-ray wavelength tables.
Palladium goes much higher. Lots of "holes in there, Robin. :-)
Fred
