Oops,to do the algebra right and put all of the constants
where they belong:
E* r = hbar*c
As energy (E ) increases, radius ( r ) has to decrease
and vice versa.
This will satisfy mcr = hbar for conservation of
momentum (spin) and energy.
Fred
>
> Electrons and positrons are routinely ejected from
> radio-nuclei and K capture takes an electron
> with a circumference or wavelength = hbar/mc
> into the nucleus where it's spin stays at
> mcr = hbar/2(pi) indicating that the nucleus
> has share energy from it's own subunits to donate
>to the electron in order shrink it down to fit.
>
> IOW, in order for mcr = hbar/2(pi) m= E/c^2
>
> satisfies this simply by the product of E* r changing
> to keep spin equal to hbar/2(pi) [E* r = hbar/2(pi)]
