Deborah D. L. Chung has been on this issue for some time, the following
links may be of interest in ref. to the carbon resistor and excess energy.


The Chung's Negative Resistance experiment
Dr. Deborah D. L. Chung, professor of mechanical and aerospace engineering
at University at Buffalo (UB)

http://jlnlabs.imars.com/cnr/index.htm

Created by Deborah Chung, Niagara Mohawk Professor of Materials Research in
the UB School of Engineering and Applied Sciences
Thermal Paste To Help Minimize Overheating In Electronic Devices

http://www.sciencedaily.com/releases/2003/07/030714092651.htm



http://jim.sagepub.com/cgi/reprint/17/1/57.pdf

http://scitation.aip.org/getabs/servlet/GetabsServlet?prog=normal&id=APPLAB0
00087000013133118000001&idtype=cvips&gifs=yes

-----Original Message-----
From: Paul [mailto:[EMAIL PROTECTED]
Sent: Monday, November 13, 2006 11:27 AM
To: vortex-l
Subject: [Vo]: 2nd law of thermodynamics is incorrect


Carbon resistors generate more thermal voltage noise
than Metal film resistors. That by itself proves
nothing, but when applied to an antenna with radiation
resistance we disprove the 2nd law of thermodynamics.
Consider two experiments where the only difference is
one uses a noisier resistor as a voltage source.

Preface: Radiation resistance generates no thermal
noise.

Experiment A:
Resistor in series with an antenna.
Thermal noise source resistance: R
Antenna radiation resistance: Rr
RMS thermal noise: Va
RMS current: Va / (R + Rr)
Radiated power: I^2 Rr = (Va / (R + Rr))^2 * Rr

Experiment B, with noisier resistor:
Resistor in series with an antenna.
Thermal noise source resistance: R
Antenna radiation resistance: Rr
RMS thermal noise: Va * 1.1
RMS current: Va * 1.1 / (R + Rr)
Radiated power: I^2 Rr = (Va * 1.1 / (R + Rr))^2 * Rr

Experiment B radiates more power.  Experiment B will
be cooler than experiment A.

Lets simply. Neither experiment A or B have a power
source except thermal noise. Experiment B radiates
more power. It is a very simple circuit. Over time,
more energy is leaving experiment B than experiment A.
Therefore experiment B will be colder than experiment
A.


Regards,
Paul Lowrance





____________________________________________________________________________
________
Sponsored Link

Degrees online in as fast as 1 Yr - MBA, Bachelor's, Master's, Associate
Click now to apply http://yahoo.degrees.info

Reply via email to