Indeed Robin, as you wrote some time ago, the small radii of the hydrinos (shrunken H atoms) if they exist would facilitate the close encounters required for fusion.
This reminds me I had promised Fred I would post a derivation of allowed (unshrunken) circular electron orbits radii in Bohr's semi-classical model for the H atom, here is one (it may not be the shortest route, improvements/comments welcome): -------------------------------- Notations (values in SI) ----------------- k coulombic force constant (8.99*10^9) me electron mass (9.11*10^-31) e electron charge (1.6*10^-19) h Planck's constant (6.6x10^-34) v orbital velocity r orbit radius n integral number (of wavelengths in orbit circumference) F=ma (Newton's 2nd law) ---- k*e*e/r²=me*v²/r k*e²=me*v²*r r=k*e²/(me*v²) (1) Bohr's postulate: orbit circumference is a multiple of the electron's velocity-dependent De Broglie wavelength h/(me*v) (which I view as a condition of non self-destruction of the electron as a wave. Such self-destructive interference would be the main obstacle to my believing in hydrinos if the wave particle duality made total sense to me ;) ------------------- n*h/(me*v)=2*pi*r (2) (1) and (2) => n*h/(me*v)=2*pi*k*e²/(me*v²) n*h*v=2*pi*k*e² v=2*pi*k*e²/(n*h) (2)=> r=n*h/(me*v*2*pi) r=n*h/(me*2*pi*(2*pi*k*e²)/(n*h)) r=(n*h)²/(me*(2*pi)²*k*e²) r=n²*(6.6x10^-34)²/(9.11*10^-31*39.4*8.99*10^9*((1.6*10^-19)²))) r=n²*52.7*10^-12 m One recognizes the 52.7 pm base level Bohr radius so it must be right ;) ----------------------------------- Michel ----- Original Message ----- From: "Robin van Spaandonk" <[EMAIL PROTECTED]> To: <vortex-l@eskimo.com> Sent: Saturday, December 16, 2006 3:52 AM Subject: [Vo]: New Hydrino page posted > Hi, > > I have just put up a new Hydrino page for those who are interested. Please > see:- > > http://users.bigpond.net.au/rvanspaa/Molecular%20Hydrino%20Fusion.htm > > Regards, > > Robin van Spaandonk > > If "other people" can be denied their rights, then what's > to stop someone claiming that you belong among the "other people"? >