Only if V or I is the Root of the Mean Square of the instantaneous value (RMS value), which is not usually what a multimeter displays in the DC setting BTW (it displays the average value).
Michel ----- Original Message ----- From: "Harry Veeder" <[EMAIL PROTECTED]> To: <[email protected]> Sent: Monday, January 22, 2007 8:16 AM Subject: Re: [Vo]: Bruce Depalma & "Free Energy > If the resistance is a constant, then would either (V^2)/(R) or (I^2)(R) > equal average power? > > Harry > > Michel Jullian wrote: > >> As discussed here before, if any or both of the current and voltage is >> constant then power can indeed be measured as simply as you said, otherwise >> it >> can't. It is a common mistake (or fraud) in overunity claims to pretend that >> average I times average V is equal to average I*V (power) when the signals >> are >> both time-varying. It is also common to believe (or pretend) that they are >> constant by not looking at them with the right time resolution. >> >> Michel > >
