I mean besides keeping the same water warm. e.g. what happens when you begin to use the hot water for washing?
Harry Michel Jullian wrote: > When you begin to use the heat from the hot reservoir (launch the Sterling) it > would tend to cool down from the thermal watts you draw from it, but since > simultaneously you pour more thermal watts into it than you draw from it it > heats up instead, with the extra heat coming from ambient air. > > Jones may be right 40% may be overestimated for the Sterling's efficiency, > let's use his figure 15% instead, but Ron may also be right that I grossly > underestimated the heat pump COP. If indeed heat pumps can easily run at > COP=9, the overall COP would be: > > 0.15*9=1.35 which would be even more overunity. > > Sterling draws 1000W heat from hot reservoir (not necessarily water BTW) and > outputs 150W mechanical. > Heat pump draws 150W*9=1350W from ambient air and outputs them to the hot > tank. > Net power into the hot tank: 350W > > Anything wrong with this Jones? ;-) (someone "read" by Jones please answer > this post so he gets it, thanks) > > Michel > > ----- Original Message ----- > From: "Harry Veeder" <[EMAIL PROTECTED]> > To: <[email protected]> > Sent: Sunday, March 04, 2007 5:36 PM > Subject: Re: [Vo]: Re: Loop closed? (was Re: High efficiency electrolysis) > > >> What happens when you begin to use the hot water? >> >> Harry >> >> Stiffler Scientific wrote: > ... >>> Enough of that, I hope some one will comment on your idea as I have seen >>> Heat Pumps easily fun at COP=9 and if I remember my reading can go to COP=12 >>> (theory). If that is the case then maybe you have just not accounted for all >>> of the loss that will take place. Indeed for Texas (most of it) a m2 of >>> blackened copper collector can get you some real hot water. >>> >>> >>> -----Original Message----- >>> From: Michel Jullian [mailto:[EMAIL PROTECTED] >>> Sent: Saturday, March 03, 2007 8:15 PM >>> To: [email protected] >>> Subject: [Vo]: Re: Loop closed? (was Re: High efficiency electrolysis) >>> >>> >>> OK, if the MIBs didn't intercept my posts which they probably didn't (no one >>> has knocked at my door yet), it must be that my scheme was simply not clear >>> enough to provoke feedback. I'll try and make it clearer through a practical >>> embodiment: >>> >>> Say we have an insulated hot water reservoir, pre-heated by a joule heater >>> (used only to start the process), as the hot source, and ambient air as the >>> cold source. An average efficiency Sterling engine (efficiency=40% >>> conservatively, say 1000W heat in, 400W mechanical out) runs on those hot >>> and cold sources (2LoT not broken), and through an appropriate >>> quasi-lossless gearbox replaces the electric motor powering the compressor >>> of an average performance house heating type heat pump (COP=3 >>> conservatively), which therefore pumps 400W*3=1200W of heat from the ambient >>> air to the hot water reservoir. >>> >>> 1000W out, 1200W in, surely there can be no doubt that after the initial >>> joule heater kick this apparatus will run standalone, drawing its energy >>> from the ambient air (cooling it so ventilation will be needed, by say a 10W >>> fan), and providing nearly 200W continuous excess heat to the hot water >>> reservoir? >>> >>> Does it make more sense now? ;-) >>> -- >>> Michel >> >
