Hi Thomas, The (fictitious, or apparent) force you're talking about is a function of _rotations_ (not revolutions) per second, and also of your mass and of your distance from the axis (force=mass*(2*pi*rotations_per_second)^2*radius_of_the_earth assuming you stand on the equator), nothing to do with distance traveled by the planet, and it is not centripetal (going towards the center) but centrifugal (think of fugitive = going away from the center), if it was centripetal it would not subtract from but add to actual weight, which is the actual centripetal force.
Michel ----- Original Message ----- From: "thomas malloy" <[EMAIL PROTECTED]> To: <[email protected]> Sent: Sunday, July 15, 2007 10:02 PM Subject: [Vo]:centripital force question > I'm subject to weight loss produced by the centripital force produced by > the earth's rotation, I'm wondering if centripetal force is a function > of revolutions per time unit, or total distance traveled as the planet > travels? > > > --- http://USFamily.Net/dialup.html - $8.25/mo! -- > http://www.usfamily.net/dsl.html - $19.99/mo! --- >
