For a rough cut, a water/electrolyte with a resistivity of 100 ohm-cm with an interface area of (pi)r^2 of 0.20 square centimeters with a hole radius r of 0.25 centimeters and a 0.20 centimeter insulating refractory washer thickness should give a resistance R = rho*area/length = 100*0.20/0.2 = 100 ohms
At 120 volts the current I would be 120/100= 1.20 amperes and a power V^2/R of 120^2/100 = 144 watts, concentrated within the cavity-interface volume of 1.0 cubic centimeter. If it doesn't form an arc plasma at 120 volts AC , it should be noisy and make 60 bubbles per second until the voltage is increased to 240 volts and the power density quadruples to 576 watts per cubic centimeter. On Dec 24, 2007 1:39 AM, Frederick Sparber <[EMAIL PROTECTED]> wrote: > Using two soup cans separated with a refractory washer with the cans > connected across 120 to several hundred volts AC or DC filled with a > water-electrolyte should hold the arc at the small diameter interface > created by the inside diameter of the washer-spacer. > > A teflon washer (or such) might suffice for trials. > > Fred >
