But the moment right before dislodgement, when the deuteron pair experiences considerable deceleration, is precisely when we would expect fusion isn't it? So I still believe we must use the CMF of the whole system under study. Similar to a hammer-nut-anvil system, if we leave the anvil out of the equation the nut will never be broken.
I am pretty sure that COE is not valid in an accelerated frame of reference BTW, except maybe in special cases. Consider a single particle in uniform motion (constant K.E.) in an inertial frame, it will see its speed and therefore its K.E. change in an accelerated frame, so COE isn't verified. Michel ----- Original Message ----- From: "Robin van Spaandonk" <[EMAIL PROTECTED]> To: <vortex-l@eskimo.com> Sent: Wednesday, April 30, 2008 1:11 AM Subject: Re: [Vo]:Re: HUP-spread-out electron "feels" (and thus Coulomb-screens?) like a point charge... - T.GIF In reply to Michel Jullian's message of Wed, 30 Apr 2008 00:37:48 +0200: Hi, [snip] >Forgive my obstinacy Robin, but admitting the proper frame should be the CMF, >shouldn't this be the CMF of all particles involved, i.e. including those of >the Pd "anvil"? After all, the target is not really D, but Pd(n)D, isn't it? This depends on just how "stuck" the D is to the anvil. Initially at large separation distances that will be true, however as the force of repulsion created by the approaching D increases it will eventually dislodge the "stuck" D, after which, it is no longer true. (Assuming the "fast" D had enough kinetic energy to dislodge the stuck D). >And who is Charles Cagle? http://www.singtech.com/ > >"hand waving" mode: quite appropriate for a wavelength ;) Frame dependence of >kinetic energy...good point... maybe we must use an inertial frame for COE >(KE+PE=constant) to be applicable, No, COE is valid for any frame of reference, as long as you stick to the frame of reference you have chosen. >which BTW points again to including the cathode for the center of mass frame, >the CMF of just the two deuterons is decelerated at impact time isn't it, >so you can't do proper physics in that frame. You only need to take "snapshots", and assume that the functions are monotonic. (not true at the moment of dislodgement). Regards, Robin van Spaandonk The shrub is a plant.