In reply to Steven Krivit's message of Fri, 27 Mar 2009 17:56:27 -0800: Hi, [snip] >http://newenergytimes.com/v2/blog/ > > You ask - "What else could it be? " and reply with "ultra-low momentum neutron-catalyzed reactions".
Here are a few other options for you:- Replace the ultra-cold neutrons with Deuterinos, and besides the ordinary fusion options, you get:- D + D -> He4 + 23.8 MeV fast electron(s) (IC). I or From a Deuterino cluster (of 4 deuterons):- 4 D -> He4 + 23.8 MeV fast deuterons (deuterinos). II or 4 D -> 2 He4 + 23.8 MeV (11.9 MeV / alpha) III In short, when lots of charged particles are in close proximity to the reaction site (fm), it's possible that those particles not actually forming part of the new nucleus absorb the energy of the reaction. (I & II) When more than 4 deuterons fuse all at once, they can form 2 Helium nuclei concurrently. (III). This may work as follows: Deuterino molecules are bound together in a cluster by magnetic forces (e.g. 4 Deuterinos in all). When the nuclear force pulls one deuteron into the nucleus of another Deuterino, the electrical and magnetic forces binding the whole together ensure that everything gets sucked in at once. The result is temporarily an excited Be8 nucleus that promptly splits into two He4 nuclei. Note that such a mechanism might also explain the Iwamura et al. results, where transmutations occur with multiples of Deuterino molecules, IOW clusters with different numbers of Deuterino molecules in them, such that 4 or 6 deuterons get added in one go (clusters of 2 or 3 molecules). In these cases, the energy is lost through the Internal Conversion (IC) mechanism, due to the shrunken Deuterino electrons that got sucked in as well, then expelled at "high warp" ;^) as the nucleus rearranges itself. Note that (I) may be preferable to forming T or He3, because the He4 nucleus is far more stable, and thus the preferred option when a particle based means of disposing of the energy is available. I.e. in this case IC with a greatly enhanced probability due to the proximity of the shrunken electrons. Furthermore, the occasional occurrence of T in some CF experiments would be explained by a slow tunneling reaction between two larger deuterinos, where the shrunken electron is not so close, and the IC option thus reduced compared to the more usual D + D -> T + P reaction. IOW the size of the Deuterinos involved would influence the branching ratios, and since there are lots of different sizes possible, the results are going to be "all over the shop". Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/Project.html
