On Oct 11, 2009, at 6:21 PM, Mauro Lacy wrote:
Horace Heffner wrote:
...
"The third motion in inclination is consequently required. This
also is
a yearly revolution, but it occurs in the reverse order of the
signs,
that is, in the direction opposite to that of the motion of the
center.
The above just talks about the apparent slight daily apparent
retrograde motion of the stars due to the difference in the sidereal
day (23 h 56 m 4.1 s) vs the solar day. This is merely an aspect of
the earth rotating around the sun in the ecliptic. See:
http://scienceworld.wolfram.com/astronomy/SiderealDay.html
The apparent motion of the stars is thus in the opposite direction of
the sun's motion, because at the same solar time very day the earth
has rotated a an extra 4 minutes so the overhead position has
advanced relative to the stars - making the stars appear to move
retrograde (backwards in relation to the sun's movement.)
This is just a ramification of the earth moving in the ecliptic.
And that is is an interpretation.
I don't think so. Ask any accomplished astrologer. 8^)
Look, these are matters of interpretation, and also of personal
choice,
to a certain extent. And that's very important.
I really don't think that is possible. There is indeed a slight
apparent retrograde motion of the stars, and it is at an inclination
to the ecliptic. (The poles of the earth's rotation don't match the
poles of the ecliptic.) It amounts to a yearly revolution. It occurs
in the reverse order of the signs (astrological solar houses), i.e.
is retrograde. It is merely an aspect of the earth rotating around
the sun in the ecliptic. It is due to the earth midheaven (or nadir
etc.) at any location rotating, with respect to the fixed sky,
roughly an extra 4 minutes every solar day, i.e 24 solar hours. This
makes the stars seem to be located behind where they were the prior
day, which is an illusion due to the rotation of the earth around the
sun. The sun is off position (with respect to the fixed stars) 4
minutes a day due to the earth moving forward in its orbit. At
midnight different stars are at the midheaven, and the old stars
appear to move about 1 degree of arc retrograde, i.e. (4 m/(24 h*60
m))*360 degrees = 1 degree. In one siderial day the earth rotates
360 degrees with respect to the fixed stars. In one solar day the
sun rotates 360 degrees with respect to the sun. Since the earth
advances about 1 degree in its orbit, the siderial day is about 4
minutes shorter than the solar day.
I think the language is clear and it is correct. Maybe it is just
hard to understand for anyone who has not read a lot of old astrology
texts.
Of course, Bill Beaty might say my bias is showing again. 8^)
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
