Horace, 2009/11/26 Horace Heffner <[email protected]>: <snip> > Here is the original explanation, less the garbled indicator test > information: > - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - ... > It is the presence of the high concentration of ions in > solution that makes the residual potential when the battery is disconnected. > The H3O+ ions take on electrons through the wire originally releasing > hydrogen at the site where the hydrogen was generated, the anode, thus > making *more* hydrogen bubbles. Similarly, the OH- ions donate electrons to > make H2O2 and *more* O2 at the site where O2 was generated prior." > - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - > > > Still looks right to me, despite the fact I remain dizzy! <snip>
Well no, the site where the hydrogen was generated (which was the cathode BTW, not the anode, let's call it the negative electrode rather, as anode and cathode names switch sides when current direction is reverted) was surrounded by OH- ions, and the site where O2 was generated prior (which was the anode, let's call it the positive electrode from now on) was surrounded by H3O+ ions. Therefore it can't be a case of "more H2 where H2 was already bubbling and more O2 where O2 was already bubbling", agreed? Michel
