At 01:24 AM 3/18/2010, [email protected] wrote:
He states that it must be OU because the output voltage goes above the battery voltage.
B O G U S. If the output were charging the exact same battery, that would mean something.
In this sense, it was correct that you can't tell from voltage alone. The same amount of power stored in a small capacitor would show a very high voltage, with a large capacitor a low voltage.
However has he taken into account that the two coils form a transformer, and it's very possible that the secondary has more windings than the primary, so that the output voltage is higher than the input voltage?
Lots of ways to do it. Voltage is like water pressure. With a constant pipe going up, you can tell how much water you have (and thus how much stored energy) by the pressure. But you can extract energy from a lot of elevated water and use it to raise a small amount of water much higher. Smaller pipe! If you simply connect the two pipes, the pressure will equalize, and the water will have a head that is the same, because the pressure does not depend on how much water you have, only the height of the column. But when a big column moves down, it generates so much power which can be used -- try some gears! -- to raise a small amount of water much higher. Other things being equal and without losses to friction, you could raise a certain amount of water twice as high as you lower half the amount of water.....
