Lane and I may prove to be like Bohr and Einstien. Lane did not understand why the velocities of the nuclear wave and electronic waves had to be equal under the condition of quantum transition. I was not completely happy with my derivation of the probability of transition.
We finally arrived an analogy to explain this were the velocity of sound in the nucleus was like an ocean wave. The electron rides this wave like a surfer. When the speeds of the two waves(mechanical and electrical) matched energy flowed and a quantum transition took place. What then determined the probability of transition? It was the probability of the surfer catching the wave. I think I can rewrite the probability of transition in terms of the probabiloity of catching a wave. Thanks Lane. Frank
