Here's another way to use Vt in a prediction. Because it looks as though Vt can be used to derive Planck's Constant, then use Planck's Constant to calculate a very accurate Vt. I don't know how accurate these other variables have been measured, but presumably, they are far past the 4 significant digits of Vt. So, by back-calculating Vt, we can then use it to predict the effective radii of protons in the nucleus, which is the variable that seems to be the least certain. Then we just need another experiment to more accurately determine the effective radii of protons while in the nucleus.
E = (Q^2 / (4 * e0 * Vt)) * f E = h * f (This is Einstein's Photo-Electric Equation) h = Planck's Constant Solving backwards for a better Vt = Q^2 / (4 * e0 * Vt) = h Q = charge of a proton = 1.602176487*10^−19 Coulombs e0 = permittivity of free space = 8.854187817*10^−12 (http://en.wikipedia.org/wiki/Vacuum_permittivity) 4 * e0 * Vt = Q^2 / h Vt = Q^2 / (h * 4 * e0) Vt = (1.602176487e-19)^2 / (4 * 8.854187817e-12 * 6.62606896e-34) = 1,093,845.63 Craig
