In reply to Stephen A. Lawrence's message of Fri, 08 Apr 2011 12:43:52 -0400: Hi, [snip] >At the point where the effluent is at 60 degrees, it's taking 300 watts >just to heat the flowing water. However, at that point "ignition" takes >place, and another heat source begins to warm the device. Since the >joule heater is taking care of warming the water (at 60C), all the >*additional* heat will go into warming the device.
I think some of the additional heat also has to warm the water to more than 60 ÂșC (since the temperature of the water also goes up with the temperature of the device). > So, the slope of the >curve at that point corresponds to however much heat is being generated >by the reaction, applied solely to warming the device (as, again, the >heater's output is sufficient to warm the water to that temperature). >I've drawn a tangent line to the curve at 60 degrees in blue. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/Project.html

