Dear Peter,
I do not understand the problem. There are two systems involved: heat and electricity At the system level P-out is thermal and refers to net heat. The calorimetry determines P-out for heat. P-in for the system, not for the calorimetry, is determined by the sum of all the electrical inputs. The pump must be included as it is necessary. There is nothing in the calorimetry loop which is used to determine *system P-in*. Yes the heat loop itself may have it own designation for P-in and P-out, but that is not for the system; that is why I believe you could be conflating the two issues. Jones From: Peter Gluck Want I wanted to say- the pump is part of the cooling circuit to which the heat produced is transferred. Has nothing to do with the heat produced. peter On Wed, Apr 20, 2011 at 6:15 PM, Jed Rothwell <jedrothw...@gmail.com> wrote: Peter Gluck wrote: Fortunately the inlet temperature of water is measured and this includes or, if you wish excludes the effect of the pump/motor. But he effect is negligible- and not on the side of Pin- it is at Pout. No, not Pout. The heat from the pump shows up past Pout, at the place where the water stops moving. That would be either in your drain pipe, or -- if you recycle the water -- in the reservoir tank. As long as the water is moving at the same speed as it did when it left the pump, the energy has not yet converted to heat. - Jed -- Dr. Peter Gluck Cluj, Romania http://egooutpeters.blogspot.com
