Marcia Pires
July 30th, 2011 at 11:24 AM

Dear Andrea Rossi,
How much heat of the reactor is absorbed by the water and how much is absorbed by the solid parts of the e-cat?
Best wishes,
Marcia Pires

Andrea Rossi
July 30th, 2011 at 11:52 AM

Dear Marcia Pires:
The reactor is very well insulated, so that, once in equilibrium, the heat loss from the reactor is very low. Still, some heat is lost. We calculated 100 wh/h per E-Cat. Good question, thank you.
Warm Regards,
A.R.

[ wh/h =  W of course ]

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