Of course you are correct with your statement that we only have his word and the consultants data to operate upon. But, many of the facts (assumptions) have been reasonably established earlier. The water storage volume of 30 liters seems appropriate and the calculation of power output from input flow rate and temperature delta is thermodynamics. Do you think that the engineer is not Domenico?
Can you tell me a method for obtaining any information what so ever if we wish to analyze the test? I consider it a little too timid to give up without at least an effort. This is not a court of law, we are engineering a system. What do you suggest? Do you think it wise to use the word assumptions for some of these? I do not care what they are called, I just would like to have information to use in simulations. Throw away that lawyer hat and put on one that is more useful. Dave -----Original Message----- From: Andrea Selva <[email protected]> To: vortex-l <[email protected]> Sent: Mon, Nov 7, 2011 1:43 am Subject: Re: [Vo]: October 28 Established ECAT System Facts Hi David how do you consider facts these data ? All we have in our hands are Rossi's claims. 2011/11/6 David Roberson <[email protected]> I would like to have access to the known facts associated with the latest test of the 1 MW ECAT system. Is it possible for us as a group to keep a list of what we know must be true about the test and other facts that influence the measured performance? I am including a beginning list that should be reviewed for accuracy and appended to by vortex members. Thank you. 1). The ECATs were preloaded with water prior to beginning the test. a). A reasonable estimate of the water held within the 107 ECATs is 107 units x 30 liters/unit = 3210 liters. b). The water within the 107 ECATs is replaced in approximately 3210 liters / 675.6 liters/hour = 4.75 hours. 2). There is no pump within the output path between the ECAT’s and the large water storage tank. a). This configuration absolutely demands that the output vapor must be greater than atmospheric pressure. This is necessary to push the water out of the dissipaters. b). This pressure can be estimated by someone who is skilled in the calculation of liquid and vapor flow through pipes and dissipaters. 3). The average input water flow rate for the ECAT’s was 675.6 liters/hour. a). The output flow rate is 675.6 liters/hour / 3600 seconds/hour * 1000 grams/liter = 187.667 grams/second. Using this value and information from NIST leads to the following conclusion. b). 105 C is the average temperature output of the system, and 18 C average input. c). If only liquid water is ejected by the ECATs, the minimum system power output is 187.667 grams/second * (440.27 joules/gram liquid at 105 C – 75.544 joules/gram liquid at 18 C) = 68.45 Kilowatts. d). If vapor is the only output then the maximum system power output is 187.667 grams/second * (2683.4 joules/gram vapor at 105 C – 75.544 joules/gram liquid at 18 C) = 489.4 Kilowatts. e). The true power output of the system must lie between these two values. 4). The customer had an engineer named Domenico Fioravanti and helpers to verify operation of the system. Dave
