How do you know how much go to photons and to neutrinos? 2012/1/2 Horace Heffner <[email protected]>
> > On Jan 2, 2012, at 7:10 AM, Daniel Rocha wrote: > > Alright, so the most probable reactions are those that minimize the energy > spent at any given time. That is, those that require the least binding > energy for the deflated proton. But, shouldn't that mean that Ni58 is the > one that gives more energy? After all the number in bracket is the smallest > energy in the bracket. > > > First, each reaction line on page 1 is independent of the others. What > happens to 58Ni is independent of what happens to other isotopes, and only > dependent on its abundance in the lattice. > > The trapping energy only ensures that follow-on weak reactions are > feasible. Note the large energy deficits and thus trapping energy that > immediately results when one of the electrons is absorbed into a neutron. > > In any case, the bottom line is the reaction: > > 58Ni28 + 2 p* --> 60Ni28 + 2 v + 18.822 MeV [-0.085] > > produces comparatively little enthalpy because about 18.5 MeV is carried > away by the two neutrinos. It is by far the most energetic reaction > channel compared to the alternatives: > > 58Ni28 + p* --> 59Cu29 # + 3.419 MeV [-4.867 MeV] > 58Ni28 + 2 p* --> 56Ni28 # + 4He2 + 5.829 MeV [-10.650 MeV] > 58Ni28 + 2 p* --> 60Zn30 # + 8.538 MeV [-7.941 MeV] > > given the assumption that the initial intermediate nucleus was formed by a > Ni+2p* reaction. > > Best regards, > > Horace Heffner > http://www.mtaonline.net/~hheffner/ > > > > > -- Daniel Rocha - RJ [email protected]
