Here is a chart of Boiling Point versus pressure. http://www.engineeringtoolbox.com/boiling-point-water-d_926.html My guestimate for the pressure (judging by the sound and appearance of the "geyser") is probably not more than 50 PSI. If that guess is correct it means the water in the 'pressure cooker" could be about 140 C. That would make quite a good heat reservoir to draw on during the alleged unpowered test. Presumably the vessel is quite separate from the water being pumped through the Ecat but is thermally coupled via a heat exchanger.
How much energy could be drawn from that heat reservoir? Well, let's assume that at the start of the unpowered test the water in the reservoir is at 140 C and that at the end of the test it is at 110 C (thus allowing the output temperature to remain above 100C. Delta T = 30 C Let's say that the volume of water is 20 Litres. (could be more) Calories stored = 20,000 x 30 = 600,000 Calories = 0.7 Kwh Interesting! .Notes The calorie, or gram calorie, is the quantity of heat required to raise the temperature of 1 gram of pure water 1°C; Convert calories to Kwh http://www.calculateme.com/Energy/calories/ToKilowattHours.htm
