A potentially useful hypothesis appeared in 1990 to explain the P&F effect,
one of many which are largely forgotten today. There were a number of papers
on a this new bound hydrogen species, called the "binuclear atom", authored
by Cerofolini and Para - who moved on to other fields in the mid 90s. One
paper appeared in Fusion Technology and is still online:

http://paolo.accomazzi.net/coldfusion/CanBinuclearAtomSolveTheColdFusionPuzz
le.pdf

Their hypothesis is worth a revised look today in terms of Ni-H, even though
the primary emphasis (at the time) was deuterium fusion to helium, i.e. cold
fusion. They did not consider protium as being active (and being fermionic,
having no recourse to some new kind of BEC). But a recently proposed reuse
of that term "binuclear atom" has expanded the relevance of the original
concept, and can perhaps help explain gain in Ni-H. 

Caveat: the term "Deep Dirac States"  has been used for this
binuclear/Millsean field; and Kim, Rice and others - have tried to disprove
parts of the possibility (in a flawed paper that is in the LENR archive):
http://lenr-canr.org/acrobat/RiceRAcommentsona.pdf

But rather than get into why Kim, et al, have made the wrong assumptions on
this - we should understand what the binuclear atom (not a molecule) happens
to be, first, and then the limitations on how this species can lead to gain
(which is "not exactly nuclear"). In the binuclear atom, two protons become
bound as pairs, held together by electron charge, but not as a molecule. The
atomic-like configuration is designated as (H+H+)2e-.  The easier
designation for email postings is "(pp)2e" . The activation energy of
formation is ~30 eV, which is so similar to Mills' 27.2 eV that this species
can serve as an alternative to Mills hydrino-hydride, using some of his
theory. The two protons, despite Coulomb repulsion, become bound by several
eV, which is less than molecular bonding, but fairly stable. This is
indicative of formation inside a Casimir cavity. Now if we add the proviso
that the Casimir cavity (or pit) is composed of a porous active metal (for
instance Raney nickel) then we are well on our way to an alternative take on
Ni-H energy gain and we avoid the objections of Kim. Cavity confinement
during (pp)2e formation is a key.

Unfortunately for Cerofolini and Para, they did not invoke cavity QED for
the formation of the species, nor did they understand precisely how energy
gain is possible from protium, yet with no fusion or conversion to a
neutron. In fact, they went on to focus almost exclusively on
deuterium-palladium fusion, and to helium as the result. 

More recently a paper turns up which proposes another piece of the puzzle:
"A binuclear atom - a special type of close bound state between proton and
heavy atom" Chaly, Gurevich, et al. 2007. In this one, they propose: "It is
established within the Thomas-Fermi model that a bound state of a proton
with a heavy atom should exist. On the one hand, the electrons of the atom
screen the proton's field. This decreases the repulsion force between the
proton and the nucleus. On the other hand, the attraction force between the
proton and the electrons is directed towards the gradient of electron
density, i. e. towards the nucleus. For instance, for Z=80 both forces
become equal at approximately 0.6a where a is the Bohr radius. The
corresponding minimum of the proton potential energy is in the region of
negative energies (attraction) that can be of the order of several tens of
eV. We propose to call such a system a binuclear atom."

http://arxiv.org/abs/physics/0606082

In contrast to the molecular state (nickel hydride) where a coupling of
atoms is due to shared outer electrons, the formation of a binuclear atom is
a collective response of inner electrons to the screened potential of a
proton (or pair) that is stable inside the valence shell of the heavy atom.
OK this could be another piece of the jigsaw puzzle, but we are still not
there yet. When you combine this hypothesis with that of Cerofolini (plus
the proviso of Casimir containment) then you can see the possibility of a
binuclear hybrid where the (pp)2e species forms in a cavity and then becomes
nested inside the collective electrons of a heavier host atom, which in this
case is nickel.

But all of this activity  is endothermic. The final step is to describe how
this metastable arrangement translates into net energy in a way that is "not
quite nuclear".  For this you need to look at nuclear mass depletion which
does not (normally) result in any kind of transmutation. 

For instance, the mass of a proton can vary within a range around 938 MeV,
which is an average and not quantized. Since only the three quarks are
quantized, there is plenty of room for mass-to-energy conversion of binding
bosons (pions gluons etc). Quarks account for a small part of proton mass -
far less than half, depending on who you believe, and the non-quark mass is
substantial and variable, to the extent that there can be a surplus in many
atoms, some of which is extractable. This mass-to-energy conversion without
transmutation shows up as the acceleration gradient of formerly bound
protons (away from each other) when they occasionally approach within the
limits of the strong force (but cannot bind due to Pauli).

There you have it. At least for today.

Jones

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