>If two neutrons were capable of binding, then one might expect them to
occasionally do so with the aid of a third particle with which momentum could be
shared resulting in an energetic third particle and an energetic di-neutron.
Hence one would expect to occasionally detect di-neutrons. AFAIK none have ever
been reported. I suspect that neutrons do indeed repel one another at very close
range because of their negative near field.<


I also would expect a di-neutron combination if it formed to beta decay into 
H2.  There can not be adjacent equal nucleon count elements since a beta decay 
will always occur.  Perhaps this is what happens to any di-neutrons that are 
formed.  How would one capture one of these beasts if it in fact did form?

A similar decay should take any di-protons out of the mix if they formed.  This 
is an interesting subject to follow up on.  Beta decay is an efficient way to 
reach the lowest energy state for equal nucleon count elements.

Dave



-----Original Message-----
From: mixent <[email protected]>
To: vortex-l <[email protected]>
Sent: Sat, Jul 14, 2012 6:02 pm
Subject: Re: [Vo]:Repulsive interactions between neutrons


In reply to  David Roberson's message of Sat, 14 Jul 2012 01:15:00 -0400 (EDT):
i,
snip]

I want to put in my 2 cents worth concerning repulsion between neutrons.  If 
wo neutrons meet in free space I would think that they would be attracted 
ogether by the strong force.  The reason that this combination would not remain 
ogether might be that there is no path available for the binding energy to 
scape before they fly apart.  The deuterium nucleus has one neutron and one 
roton that can remain together since the accelerated proton with its charge 
mits electromagnetic radiation.  Hopefully, once some binding energy is 
eleased the two nucleons would not have sufficient energy remaining to rebound 
part.


Robin, I am hoping that the coupling or entangling of your proton cluster with 
he proton entering the target nucleus will absorb much of the released binding 
nergy at a controlled rate and prevent the emission of high energy gammas.   It 
s my opinion that the high energy gammas must not be emitted at any time. 
snip]
f a proton cluster fuses with a Nickel nucleus, than many reactions become
ossible, including cold fission reactions where most of the energy appears as
inetic energy of the fission fragments. Such fragments are heavy and slow, and
ill not produce any bremsstrahlung of significance.
This is essentially what happens in current fission reactors. However in these
eactors the trigger particle is a neutron, and the nuclei are already very
eavy to start with, so the daughter nuclei are always going to be neutron rich,
nd hence frequently radioactive.
When the triggering "particle" is a proton cluster, the excess neutrons are
ompensated for by the additional protons, and the daughter nuclei can be stable
as they would prefer to be - stability implies an energy minimum).
This is especially true if the initial nucleus is not too heavy, i.e. doesn't
ave too large an excess of neutrons.
Regards,
Robin van Spaandonk
http://rvanspaa.freehostia.com/project.html

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