I do not think all of the energy can be carried away by means of a neutrino emission since the remaining nucleus must rebound to preserve momentum. This of course would also require energy to be impressed upon that nucleus in the form of 1/2*m*V*V. Not much, but at least a tiny bit of energy. Robin, are you confident that a gamma is not released at the same time as the neutrino?
Dave -----Original Message----- From: mixent <[email protected]> To: vortex-l <[email protected]> Sent: Sun, Jul 22, 2012 6:46 pm Subject: Re: [Vo]:principles of DGTG 's technology In reply to David Roberson's message of Wed, 18 Jul 2012 16:14:39 -0400 (EDT): i, snip] And of course we have been searching very hard to find a process that does not elease strong gammas and this would fit that requirement as long as we overlook he 511 keV ones. There are actually two processes by which protium fusion occurs. The second is he p-e-p reaction, where an electron is captured concurrently. This second rocess is rare compared to the emission of a beta+, but does happen. When it oes, no positron is emitted, and consequently no 511 keV gammas are produced. severely shrunken f/H may result in p-e-p taking precedence over p-p. nfortunately AFAIK, all the energy of the p-e-p reaction is carried by the eutrino which of course escapes, hence no net measurable energy effect. :( Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
