>Perhaps the best issue to be noted is the spinning electromagnet manifested as
>a field of a car alternator. No where do I see it mentioned, except in my own
>research: that there is a correct direction for the DC field currents to be in
>harmony with the rotation. This only stands to be common sense where it comes
>to drift velocity, for the field rotation and its current to be delivered from
>non moving slip ring contacts; one method will deliver current in agreement
>with the drift velocity direction, while the other will detract from it
>showing as a reduced stator voltage. There are numerable proofs that counter
>the remanent magnetism and parametric case as the cause for power output
>without field energization. Here is some further scribbling of notes never
>sent when this subject last came up....
Once when I was more naive I thought about the magnetic field surrounding a
wire broken by a capacitor coupling device. As I visualized the magnetic field
due to the current, I began to think that there must be a gap or discontinuity
since no real current is flowing within the capacitor. Between the plates
there is only an electric field that is changing as charge is being added or
subtracted from the plates of the capacitor.
Now I will explain something that NO ONE has ever answered!
It even bothers the theorists who explain it away as a heating loss of wires or
something. Or they say it was lost as the magnetic field around the wires
connecting the parts. The big dummies never even considered that it was lost as
the magnetic field movement around the capacitor itself! Thus they have not
thought to put in special collectors of this lost energy; and then reconvert
that lost energy back into another capacitor. Let me know if you think this can
be done.
I have two equal C values. I charge one up and find the joules of energy
contained in it. Now I take the other unused C value and allow one to charge up
the other to equilibrium. Now I compare the total amount of energy contained in
both parts and find only half the original amount of energy! Where did the
missing energy go to? CAN I MAKE AN ARRANGEMENT WHEREBY MORE THEN HALF THE
ENERGY MAY BE SHARED BY BOTH OF THE CAPACITORS?<
Take a relatively large inductor and place it in series with the second
capacitor. This added inductor augments the already existing built in
inductance due to the construction of the capacitors and the distance required
to complete the connection. If the total inductance exhibits a low value of
series resistance at the resonant frequency (high Q) then an oscillatory
current will flow within the loop at that frequency. You will observe that
energy is stored within the inductor as 1/2*L*I*I as well as within the
capacitors in the form of 1/2*C*V*V. The instantaneous energy stored in the
three components will be equal to the original amount in the one capacitor
minus energy lost within the equivalent series resistance in the form of heat.
An oscillation will continue to appear within the series resonant circuit until
all of the missing energy is lost within the resistor. Once things settle down
the voltage will be one half of the original value across both capacitors.
If you reduce the net series inductance then the losses associated with the
series resonance will quickly absorb the energy as the frequency of oscillation
increases. You will find that some of the energy is radiated into space by the
loop and the amount radiated is strongly related to the net resonant frequency
of the system.
I would think that you could build a system where most of the energy is
absorbed by the two capacitors if a careful arrangement of inductors and diodes
is chosen as long as you did not demand excellent balance between the capacitor
voltages. The initial energy not lost in the series resistances as heat or
radiated will be stored within the two capacitors after sufficient time has
elapsed.
Dave
