On Sun, Nov 11, 2012 at 12:39 PM, <mix...@bigpond.com> wrote: All of these are explained if the active particle is a f/H molecule. > > 1. The molecule is neutral, thus is not bothered by the Ni electrons. > 2. There are no gamma rays because only one of the two protons fuses, the > other > being ejected carrying the energy of the reaction. Fusion primarily with > 62Ni & > 64Ni yields stable copper isotopes. > 3. Heat is deposited to the substrate by fast protons. > 4. The fact that the molecule is neutral gets it close enough to the > nucleus to > make tunneling possible. >
Nice trick. Now I have a better sense of some of the strengths of the f/H approach. Is there any reason these things could not happen with Rydberg H2 (in contrast to inverse-Rydberg H2), deformed under an electromagnetic field, where the nuclei are far to one end of the electron shells? Eric
