by definition, wouldnt it be both terms of the square? or am i misunderstanding the question?
On Fri, Jan 18, 2013 at 2:31 PM, <[email protected]> wrote: > When there is one equation and you substitute another equation into one > of its variables, the solution is a set of numbers that includes > the conditions of both equations. It is a simultaneous solution. > > Were there is a squared term in one equation and another equation > is substituted in for only one of the terms of the square, > what does the result mean? Its not exactly a simultaneous solution. Does > it have a name? > > Frank Znidarsic >
