I am reading through Piantelli, Bergomi and Tiziano's 2013 EP2368252B1
patent [1], trying to understand the basic mechanism that is thought to be
the source of the heat they're generating.  Here I will attempt to
reproduce their description in my own words -- I do not know anything about
its plausibility and am just trying to understand what they're saying.  I
have attempted this elsewhere [2], but now that I read through the new
patent it occurs to me that I probably misunderstood Piantelli in my
previous attempt.

As an initial comment, Piantelli et al. refer to "nuclear reactions"
several times in the 2013 patent, but I gather that these are not intended
to be fusion reactions for the most part, but rather a reorganization of
the nucleons in the substrate nuclei (primarily nickel) to a lower energy
level.  They accomplish this through the catalytic action of hydrogen.
 There are two important activation energies; the first (1) involves
raising the temperature of the substrate above a critical level and the
second (2) involves introducing a shock of some kind to the system that
raises the energy in specific regions to an even higher level.

If I have understood the authors, the system and mechanism can be described
like this:

You need clusters of transition metal atoms of certain sizes involving
magic numbers above a minimum count and and below a maximum one, where the
metal atoms are arranged in a regular crystalline pattern (fcc, bcc,
hexagonal).  The number and atom count of the clusters determines the
potential power output. These clusters of transition metal atoms are then
exposed to hydrogen, which adsorbs onto the surface layers. If the
substrate is heated sufficiently, through nonlinear and aharmonic
interactions there will be phonons whose energy exceeds the first critical
threshold (1) mentioned above.  When this happens, molecular hydrogen will
dissociate and, through some unspecified means, H- ions will be created,
where the H presumably take on valence electrons in the transition metal
cluster.

At this point things won't go any further unless a second energy threshold
(2) is exceeded through one of a large number of means (mechanical shock,
electric current, x-rays, etc.).  If one of these triggers is supplied, the
H- ion formed in the previous steps will, through unspecified means,
replace an electron in the metal atom.  At this point Piantelli et al.
claim that the Pauli exclusion principle and the Heisenberg uncertain
principle will work together to force the negative H- ion, which is
thousands of times heavier than an electron, into an inner shell of the
transition metal atom, forming a "complex" atom that combines the
transition metal atom with an orbiting H- ion, in a manner similar to f/H
catalysis.  When this happens there will be x-rays and Augur electrons.  At
this range the H- ion will be very close to the transition metal nucleus,
and the size of the H- ion and its proximity to the metal nucleus will
force a reorganization of the metal nucleus and a consequent mass deficit,
resulting in the expelling of the H- ion as a proton and a release of
energy into the system.  This appears to be the central mechanism
responsible for heat in their account.  The proton can presumably go on to
do other things, maybe causing an occasional fusion, but the authors do not
appear to rely upon this as the primary channel.

Has anyone studied Piantelli's work enough to comment on whether I've
gotten this right or missed something important?  Can anyone (Robin?)
comment on which parts are controversial and which are accepted physics?  I
understand that you can see the emission of a gamma ray from large,
metastable nuclei, when the nucleons rearrange to a lower energy level, but
is this possible with as light an atom as nickel?

Two interesting points to note -- first, there is evidence for 1-3 MeV
protons in some of the CR-39 LENR experiments.  Second, Piantelli et al.
are vague on the question of the deuterium content.  They say that the
hydrogen can have the natural level of deuterium (0.015 percent), or it can
have a deuterium content distinct from this, but they do not specifically
say that you can use H2 that contains no deuterium.

Eric


[1] http://www.22passi.it/downloads/EP2368252B1[1].pdf
[2] http://www.mail-archive.com/[email protected]/msg72906.html

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