Andrew <[email protected]> wrote: ** > By direct admission of the team, posted here, *it did not occur to them > to check* for a DC level change. >
Okay, so they will do it next time, or the time after that. If Rossi is doing anything like this, it is inevitable that he will be caught. Sooner or later someone will use a conventional commercial watt meter. These devices are miniature calorimeters, in one mode. (They have 3 modes, as I recall, and they use all three.) They put a small resistor across the circuit and measure the temperature of it. Power is a function of temperature. There is no way you can "sneak" power past this, with any waveform, AC or DC. Andrew also wrote, in response to this: 7. Will you test the power supplied to the device with oscilloscope during > the next test? "This is a question for Prof. G. Levi who provides the instrumentation.Oops, what a giveaway." I assume this means that Andrew is convinced that Levi is part of a conspiracy, so this is a "giveaway." Okay, let me repeat what I said, modified: The next time, or the time after that , someone will use an instrument that detects this "trick." If Rossi and Levi are doing anything like this, they will inevitably be caught. They know that. There is no point to fooling people with a method that will be exposed as sure as night follows day. Andrew should address this fact. He should stop repeating this tiresome nonsense. Andrew wrote: "Thus you can supply high power at low current if you use high voltage, which is how a thin wire can be used to sneak in high power. Jed made the same mistake as you, thinking that you need high current to get high power . . ." No, I did not "forget" that. I am aware that power is I*V. However these is a limit to how much power you can conduct with any wire. You cannot conduct enough to melt a steel cylinder with an ordinary wire. - Jed
