The fact that T and He3 are typical for the hot reaction and that there is much space between reacting bodies tends to support the case that I am floating. In LENR, there are always nearby bodies to share with. The question that arises is whether or not energy can be quickly shared with the nearby objects to allow the relatively hard nut (He4)a chance to give off the fusion energy that would otherwise want to tear it asunder. (I like that word :-))
It is apparent that T or He3 are the major components released by fusion of D's when following the hot fusion path, but we need to come up with a good reason why the cold fusion case almost always yields He4 instead. I suppose that when two D's collide you can have three results. If one large nucleon is released you get T or He3. If two are emitted then I imagine you get back the two D's. If none are emitted, then He4 is a result with an associated energy release of some type. We expect for cold fusion to mainly follow the none emitted direction where the energy has to escape the cauldron in some form. If Coulomb coupling can allow that amount of energy to wind down fast enough, then we have a system. Eric has been discussing a nearby friend atom which would possibly achieve that goal, but it is quite early to know if the process has merit. Dave -----Original Message----- From: mixent <[email protected]> To: vortex-l <[email protected]> Sent: Sat, Jun 22, 2013 9:16 pm Subject: Re: [Vo]:Rossi and DGT Similarity? In reply to David Roberson's message of Sat, 22 Jun 2013 20:29:00 -0400 (EDT): Hi, [snip] > >I suppose He4 is a relatively tough little nut to crack, but it seems to >happen more often than not when D's fuse. Isn't that the reason that T or He3 tend to remain alive after a free space event? COM will always be achieved when two D's collide and remain stuck together. That isn't the momentum that's in question. It's all about the momentum of the final "bits" not the momentum of the initial bits. When a gamma is formed, it shares momentum with the 4He nucleus, thus allowing the 4He to remain in tact. However gamma production is usually a relatively slow process, and the T, 3He branches are much faster. In all cases two particles are involved. "4He + gamma" (counts as a particle because photons have momentum); "T + p"; "3He + n". Because there are two particles, momentum is conserved (i.e. always zero in CM frame). When a spectator nucleus is available, it can take the place of one particle resulting in "spectator + 4He". D + D + e (slow) => 4He + e (fast) here the "spectator" particle is an electron. This would essentially produce a 24 MeV electron. >COE suggests that they retain the amount of energy required to break apart immediately unless some of the fusion energy is released. I can not think of a better trick to pull off than for a nearby electro magnetically coupled "friend" to take away a portion of it. In hot fusion there is no one nearby to help out most of the time. I am suggesting that perhaps on those rare occasions when the He4 survives that a helper is close by. In LENR help is around the corner in most cases due to close quarters. Perhaps something like:- D + D + e (slow) => 4He + e (fast) ? here the "spectator" particle is an electron. This would essentially produce a 24 MeV electron. The problem with such an approach is that apparently a helper is almost *always* at hand, since the product is almost always 4He. If the de-energizing mechanism were independent of the Coulomb barrier penetration mechanism, and reliant upon chance, then one would expect to see much more T and 3He. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
