I am having a difficult time reconciling your calculation with what DGT shows in the video. I recall them stating that .5 liters per minute was the incoming cold water flow rate. Do you remember seeing a different number?
My initial issue is with the velocity of the steam leaving the output pipe when the temperature was around 160 C. It is not obvious what you calculated for this value and that is what I question. Sorry if this is not clear. I calculated a rough number that was in the vicinity of 100 meters per second while I believe you got much lower. I assumed pipe with an inside diameter of 1 cm which was different than you used. Is there any report of the actual pipe size used during the experiment? At this point I am assuming that I made some calculation error, but have not had an opportunity to track it down. Dave -----Original Message----- From: Alan Fletcher <[email protected]> To: vortex-l <[email protected]> Sent: Mon, Aug 5, 2013 6:29 pm Subject: Re: [Vo]:Info for Luca Gamberale (CTO Defkalion Europe) > From: [email protected] > Sent: Monday, August 5, 2013 3:19:12 PM > >m = Q / ( c * dT) = 79.2 * 10^3 / ( 4.186 * 25 ) = 79200 / 104.65 = > >756.8 kg/h = 12.6 kg/MINUTE <=== not seconds > > > >which is close to what I used. > > 756.8 kg/hr = 0.21 kg/sec (you forgot to divide by 60 to convert minutes to seconds). I typed in the units wrong at the end -- 12 kg/MINUTE, which is what Defkalion were using (liters/minute)
