Hi, Consider
Hy2 + D => 4Li* (Hy2 is a severely shrunken Hydrino molecule) followed by 4Li* decay (HL ~ 8E-23 seconds):- 4Li* => 3He + p + 5.49 MeV The reaction eats up whatever D is available, and converts it into 3He and a fast proton. Because the decay reaction is fast, no prompt gamma is produced. The energy is carried away as kinetic energy by proton & 3He. The fact that both proton & 3He are charged means that neither of them have a significant range in a solid. Because both particles are fairly heavy, only low energy X-rays are produced. Sound familiar? The Coulomb barrier for this reaction is *much* lower than for fusion with a Nickel nucleus. The cross section for the reaction should be about on a par with that for D + 3He. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
