In reply to Jones Beene's message of Wed, 12 Feb 2014 13:10:32 -0800: Hi Jones,
Note, that as Harry said, I was referring to p-e-p, not pp. The pp reaction does indeed produce a positron, however the p-e-p reaction is an electron capture reaction, and the only particles produced are a deuteron and a neutrino. Given that the mass of the electron neutrino is minuscule compared to that of the deuteron, it will get more than the lion's share of the energy. Moreover, the neutrinos from the Sun with a sharp energy of 1.44 MeV resulting from this reaction have been detected. > > >-----Original Message----- >From: [email protected] > >>The most elegant answer begins with the obvious assertion that there are no >gammas ab initio, which means that no reaction of the kind which your theory >proposes can be valid because gammas are expected. > >Actually not only would I not expect to detect any gammas from a p-e-p >reaction, I wouldn't expect to detect any energy at all. That's because the >energy of the p-e-p reaction is normally carried away by the neutrino, which >is almost undetectable. > >Hi, > >Not so - the reaction produces a positron, which annihilates with an >electron producing 2 gammas. They net energy is over 1 MeV and easily >detectable. > >Jones Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
