What would be the testable predictions of your theory? What should we be looking for when someone tests a device and publishes data about it?
On Fri, Mar 21, 2014 at 7:54 AM, Teslaalset <[email protected]>wrote: > I've been reading quite some theories and views on what exactly Rossi's / > Defkalion's processes might be. > Here's my current view focussing on the main effects only. Comments and > (dis)agreements are welcome: > > The main chain of fusions/transmutations is in my view: Ni58+p > Cu59 + e- > > Ni59 +p > Cu60 + e- > Ni59 + p > Cu60 + e- > - - - - - > Cu63 + e-. All > Cu isotopes in the range of Cu59 - Cu62 have relative short half-life. The > longest half-life is that of Cu61 (3.3 hours). This is why Rossi's > process needs quite some time to shut down. The fusion/transmutation chain > stops at Cu63 because Cu63 is stable with an extreem long half-life. > Protons (p) are provided by (absorbed) Hydrogen ions. Electrons (e-) are > released due to Vibrationally Promoted Electron Emission (VPEE). > > The released energy is caused by two sources: > > 1. The emitted electrons e- (with very high kinetic energy, 5 - 8 > MeV); the electrons are absorbed by the reactor wall causing eddy currents > that are converted into heat due to resistance of that wall material. Those > eddy currents also may be the cause of the extreemly high magnetic fields > that have been observed (Defkalion). > 2. The ß+ decay energy of Cu(x) > Ni(x) + e+ + ve (2 -4 MeV) of each > decay step in the chain, causing the Ni/Cu powder to heat up. > > Some ballpark figures on the total energy generated and the amount of fuel > involved: > Assuming all the Nickel in the reactor in the form Ni58 and finally all > transmutted into Cu63: > Ni58 mass is calculated to be 57.95380± 15 amu. The actual mass of a > copper-Cu63 nucleus is 62.91367 amu. Mass of Ni58 plus 5 nucleons is > 57.95380+5=62.95380 amu. Delta mass is 62.95380-62.91367=0.04013 amu. 1 amu > = 931 MeV is used as a standard conversion 0.04013×931 MeV=37.36 MeV. So > each transformation of Ni58 into Cu63 releases 37.36MeV of nuclear energy. > So, without further energy losses it requires 2 - 3 grams of Ni and > approx. 0.2 grams of H2 to produce 10KW of heat over a 6 months period > continuously. >
