The decay of the neutron is associated with a quark transformation<http://hyperphysics.phy-astr.gsu.edu/hbase/particles/qrkdec.html#c1>in which a down quark is converted to an up by the weak interaction . The average lifetime of 10.3 min/0.693 = 14.9 minutes is surprisingly long for a particle decay that yields 1.29 MeV of energy. You could say that this decay is steeply "downhill" in energy and would be expected to proceed rapidly
The neutron is about 0.2% more massive than a proton, which translates to an energy difference of 1.29 MeV. The large amount of excess heat reported in this system might indicate the all energy from the decay of the neutron into a proton is available excluding the condensation of the electron from the available energy of 1.29 MeV. On Fri, Mar 28, 2014 at 7:03 PM, Axil Axil <[email protected]> wrote: > If it were endothermic, it would never happen. > > > On Fri, Mar 28, 2014 at 6:32 PM, Daniel Rocha <[email protected]>wrote: > >> That's not quite correct, you should do like this >> >> D -> P + N -> 2P + e >> >> It's endothermic >> >> >> 2014-03-28 16:57 GMT-03:00 Axil Axil <[email protected]>: >> >> A neutron becomes a proton with a gain of .75 MeV, >>> >>> P + N = 2P >>> >>> >>> On Fri, Mar 28, 2014 at 3:21 PM, Daniel Rocha <[email protected]>wrote: >>> >>>> What neutron decay? Weren't you talking about deuteron yielding 2 >>>> hydrogen? >>>> >>>> >>>> 2014-03-28 15:37 GMT-03:00 Axil Axil <[email protected]>: >>>> >>>> Jones Beene said: >>>>> >>>>> "Neutron decay is exothermic, but the stripping reaction itself - >>>>> where the neutron is separated from deuterium involves kinetic energy >>>>> depletion - so yes, the net reaction is not necessarily gainful unless the >>>>> kinetic energy of the deuteron is supplied in a gainful way, or unless the >>>>> bond energy is depleted - such as in the nanocavity using a mechanism >>>>> related to Casimir - cavity QM or spin coupling." >>>>> >>>>> >>>>> >>>>> The energy of magnetic field production is derived from the >>>>> uncertainty principle in a optical cavity were the SPPs gathered are >>>>> compressed. This mechanism is lossless. >>>>> >>>>> >>>>> >>>>> The gain comes from neutron decay. >>>>> >>>>> >>>>> >>>>> >>>>> >>>>> >>>>> >>>>> On Fri, Mar 28, 2014 at 2:29 PM, Daniel Rocha >>>>> <[email protected]>wrote: >>>>> >>>>>> That's an endothermic reaction. And I don't see where it would fit >>>>>> anywhere in any scheme. >>>>>> >>>>>> >>>>>> >>>>>> -- >>>>>> Daniel Rocha - RJ >>>>>> [email protected] >>>>>> >>>>> >>>>> >>>> >>>> >>>> -- >>>> Daniel Rocha - RJ >>>> [email protected] >>>> >>> >>> >> >> >> -- >> Daniel Rocha - RJ >> [email protected] >> > >
