At 1:31 of part 1 of his July 21 demonstration Mills tells us that in order
for the Sun Cell  to produce 10 megawatts of electricity it will need to
create 25 megawatts of light energy, as the PV cells have a 40% conversion
ratio. I presume that will leave 15 megawatts to be dissipated as heat (it
has to go somewhere, right?) With that much heat wouldn't the reactor
itself nearly glow with the intensity of the sun? I'm just a simple country
doctor so probably I'm missing something.
Steve High

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