I think we can eliminate 2 kind of impossible reaction :
- those involving free neutrons that would be thermalized even rarely, and
detected
- those not geometrically balanced which would creat a gamma tha would be
detected.

geometry is the key because of CoM.
probably the electron is too, but that is not sure...

2014-10-14 7:22 GMT+02:00 <[email protected]>:

> Hi,
>
> (This email best viewed with a fixed width font).
>
> Prime candidates are even numbered elements with an odd number of
> neutrons. This
> is because subtracting or adding a neutron produces an even-even nucleus,
> and
> these tend to be stable.
>
> The reactions that yield the most energy would use a neutron source where
> the
> neutron is only bound loosely. Here is a table with some isotopes and the
> binding energy of the odd neutron (the lower the binding energy, the
> easier it
> is to remove):-
>
> Isotope Energy (MeV)    ppm of the element in the Earth's crust
> D       2.2             !
> Li7     7.25            13 !
> Be9     1.573           1.5
> C13     4.946           200
> Mg25    7.331           32000 !
> Si29    8.474           267700 !
> Ca43    7.933           52900 !
> Ti47    8.88            5400 !
> Ti49    8.142           " !
> Ge73    6.783           1.6
> Se77    7.419           0.05
> Sr87    8.428           260
> Zr91    7.194           100
> Mo95    7.369           1
> Mo97    6.821           "
> Pd105   7.094           0.001
> Cd111   6.976           0.098
> Sn117   6.943           2.5
> Sn119   6.483           "
> Ba135   6.973           250
> Ba137   6.90            "
>
> The most useful isotopes are likely to be those of low atomic number, high
> abundance, and reasonably large isotopic percentage of the element in
> question.
>
> These have been indicated with an "!".
>
> In particular, Mg25 may be an opportunity that has been missed so far. It
> is
> interesting both because of it's abundance, and because of the neutron
> binding
> energy comparable to that of Lithium.
>
> Possible interesting reaction:-
>
> 25Mg + 25Mg => 26Mg + 24Mg + 3.763 MeV
>
> Furthermore the energy is divided over two nuclei of almost equal mass,
> hence
> each gets about half (1.9 MeV), so this could be a very clean reaction.
>
>
> Regards,
>
> Robin van Spaandonk
>
> http://rvanspaa.freehostia.com/project.html
>
>

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