Some people are still confused about the input power from the pump in
Mizuno’s calorimetry. Let me point out two things about this:

1.      While there has to be some heat from the pump, with this
configuration, that heat is too small and too close to the noise to be
detected with this equipment. This is obvious from the data I uploaded.

2.      If the heat could be detected, it would still not be a problem. It
would simply be included in the baseline. In calorimetry you sometimes see
input power from the instruments themselves, or from something like a
circulation fan in a Seebeck calorimeter. The pump runs under the same
conditions at all times so power is stable and it would be easy to subtract.

Let me discuss these two points in more detail.

Some people seem to have difficulty grasping the notion that heat can be
too small to measure with a given instrument. I suppose the heat from this
pump is on the order of ~0.2 W. Based on other data I think ~0.5 W is
barely detectable with this system. The pump heat cannot be measured
because it is close to the noise from ambient temperature changes. With any
calorimeter it is always more difficult to measure at the bottom of the
scale down in the noise. You can measure the difference between 3.0 W and
3.2 W more easily than the difference between 0.0 W and 0.2 W.

Mizuno left the pump running for a day to see whether he could detect heat
from it. Looking at the water temperature for the day he did not see an
elevation above ambient. No doubt there was one, but he could not see it.
Ambient temperature changes swamped it. One minute the room is warmer than
the water by 0.2°C. A few minutes later the room heater turns off and the
reactor is soon warmer by 0.1°C. This is what I observed on October 23 when
we did not conduct testing until afternoon and I left the Omega thermometer
in the T1-T2 comparative mode. That means heat from the room is sloshing
into and out of the water, albeit at a very low rate thanks to the
insulation. Still, it is apparently doing that enough to hide the effects
of the pump. Once the water is heated above ambient, the heat sloshes *out
only*.

After the heating and air-conditioning in Mizuno’s lab is upgraded, it may
be possible to detect a slight average temperature rise above ambient
caused by the pump. If that happens we can then subtract that difference
from the temperature readings. That is what I mean by "included in the
baseline."

A low level of input power will cause a persistent average higher
temperature compared to ambient. It will *not* cause the temperature to
climb higher and higher indefinitely, until you can see it. The temperature
instead reaches a peak where losses equal input. In other words, after a
while the system functions as an isoperibolic calorimeter, not an adiabatic
one. Because insulation is not perfect.

That seems to confuse people. Let me go it over it again with an example.
On October 21 the average power measured with the reactor metal and water
is roughly 4.7 W. That is 1.4 W from the resistance heater pulses plus 3.3
W of anomalous power, ignoring losses. (If you want to estimate losses,
which I figure are ~1 W, they should all be added to the anomalous power by
this method.)

The temperature rises throughout the day as you see in Fig. 7. In Fig. 9 we
zoom in, and you can measure the water and wall temperature increase from
hour 1.0 to hour 2.0. This increase is 0.3°C, which means the power during
this time is ~3.5 W (ignoring losses). That was all anomalous power; by
hour 1.0, the effect of the pulse is gone and temperatures are in
equilibrium. If there had been no anomalous power, the curve at hour 1.0
would be monotonically dropping back to ambient, as it did in the evening
and overnight after the anomalous heat went away. (The pump has to be
contributing a little heat, and slowing down this decline, but obviously it
does not contribute enough to overcome losses, because otherwise in the
evening and overnight the temperature would not fall.)

Suppose you remove the palladium wire and input a steady ~6 W with a
resistance heater. After losses that would be about 4.7 W so the
temperature will rise about the same way it does in Fig. 7. The curve will
be fairly straight for 6 hours. However, the reactor walls and the cooling
water will gradually become much warmer than ambient. Losses increase, per
Newton’s law of cooling. Eventually, losses equal input power, and the
temperature will rise no more.

At that point we would have a poorly designed isoperibolic calorimeter with
a ridiculously long settle time. It would take months to calibrate. As
Hemminger and Hohne emphasize, with a properly designed isoperibolic
calorimeter the heat losses are predictable and controlled. They are also
fast enough to allow a calibration in a reasonable amount of time.

Because the pump constantly does the same amount of work, and it is left
running pretty much all the time, we know this terminal temperature remains
the same. So if we reduce the noise enough to detect this temperature, we
can simply subtract it. A piece of cake!

If we still can't detect it with reduced noise, it is too small to worry
about.

(To be more accurate, we could estimate how much power the temperature
indicates when nothing else is running, and then subtract that much power,
rather than the temperature.)

Let me add a note about this pump itself (Iwaki Co., Magnet Pump MD-6K-N).
In the report I wrote: “the motor runs cool and it is well separated from
the pump mechanism.” Small pumps are inefficient. This one is of excellent
quality but at maximum power it consumes 18 W to produce 3 W of pump power.
A badly designed pump will add a lot more heat to the fluid from the motor
than from stirring. This one is designed to keep the motor heat away from
the fluid. It is a cylinder, with the motor at one end and the pump at the
other, and plastic housing in between. I put my hand on the motor side and
felt it was warm. The pump side was room temperature. (I estimate the motor
side was radiating about 3 W. If it had been the ~18 W it would be too hot
to touch.) Mizuno has a cheaper pump with metal housing. He stopped using
it because the whole thing seemed to be getting warm and he thought it
might add heat to the cooling water.

I asked Mizuno to check the power input to this pump with the WattChecker
watt meter. This will tell us a little more about how much stirring power
the pump produces. However, I expect the ratio of electric power to
stirring power is not fixed at 6:1. It gets worse at the low end.

- Jed

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